Adobe Journey Optimizer

Taal · 7/15/24

Hi,

We want to show the loyalty card number in e-mails to our customers. You can have multiple loyalty card numbers, so it is an array.

We want to show the loyalty card number that starts with 2616. How can I do that?

If I make an each and then add the field, it will show every loyalty card number, but I only want to show the one that starts with 2616.

dugganab · 7/15/24

You can try this

{% let idx = 0 %}
{{#each profile._company.LoyaltyCards as |p|}}
{%#if startsWith(p,"2616") and idx < 1 %}

{{p}}
{% let idx = idx + 1%}
{%/if%}{{/each}}

dugganab · 7/15/24

You can have a helper on the following lines -

{%#if startsWith(p,"2616") %}

{%/if%}

Taal · 7/15/24

Hi,

I tried this:

{%#if startsWith(entry.LoyaltyCardNumber,"2616")%} {{entry.LoyaltyCardNumber}}

{%else if doesNotStartWith(entry.LoyaltyCardNumber, "2616")%}
else {{entry.LoyaltyCardNumber}}

{%/if%} {{/each}}

The weird thing is, that it gives back this:

2616069166373 else 2616069171476 2616069173081 2616069171506

While I defined condition 2 as doesNotStartWith.

The profile can have multiple loyalty card numbers and in this case also multiple loyalty card numbers that start with 2616

dugganab · 7/15/24

You can try this

{% let idx = 0 %}
{{#each profile._company.LoyaltyCards as |p|}}
{%#if startsWith(p,"2616") and idx < 1 %}

{{p}}
{% let idx = idx + 1%}
{%/if%}{{/each}}

How to determine which field to show from an array