Hello!
I'm using Adobe LiveCylce Desinger integrated in SAP. I have a task to hide a database-table, if the table empty is.
Normmaly we can do following to check, whether the content empty is.
if (this.REMARK_TEXT.rawValue == null )
this.presence = "hidden";
else
this.presence = "visible";
The question is, how to check in Javascript, if a table empty is.
Many thanks in advance!
regards
longholiday
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could try something like this:
function showOrHideTable(table){
var isVisible = false;
// gets the count of instance managers, event_initialize and row objects
var rowCount = table.nodes.length;
for(var i=0; i<rowCount; i++)
{
//get the class name
var myTestNode = table.nodes.item(i).className;
//ignores the instance managers and event_init
if(myTestNode == "subform")
{
var innerCells = table.nodes.item(i).nodes;
for(var j=0; j<innerCells.length; j++){
//ignores non-input boxes
if(innerCells.item(j).className == "field")
{
//check value
if(innerCells.item(j).rawValue != ""))
{
isVisible = true;
}
else
{
//hide the row
table.nodes.item(i).presence = "hidden";
}
}
}
}
}
//if any row has a value specified
if(isVisible)
{
table.presence = "visible";
}
//no value specified
else
{
table.presence = "hidden";
}
}
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If you looked at the 1st cell in teh table and it was null woudl that be a good enough test?
Paul
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I have a table currently that holds attributes from my data. If the attributes aren't specified, the rows could be empty and skip around...so it could look something like:
Header 1 |
---|
<Empty Row> |
My Data |
<empty Row> |
My Data Again |
So if I checked row1 for empty, that would be true, but I still have rows that I want to show. So i just hide the row, and set a flag to determine if any rows are visible. If there is 1 row with data, it's visible and therefore I show my table.
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