Hi
I need to generate a report on a cf model.
All content fragments (cf) that using "simple fragment" as cf model.
Is it aem query debugger only the way to find out above or is there a screen in AEM that could provide this information , report?
Thanks,
Sri
Solved! Go to Solution.
Views
Replies
Total Likes
Hi @sreenu539
In term of GUI option I would recommend to use Report Builder functionality from ACS Commons:
It is very flexible and simple to use tool. It allows to define report base on query, and generate results a a table that can be seen in AEM or download as csv file and reviewed offline on local computer.
Below is a sample configuration of report that will return list of links to CF build using Simple Fragment model.
I used following SQL2 query in my report:
SELECT * FROM [dam:Asset] AS s WHERE ISDESCENDANTNODE([/content/dam]) and s.[/jcr:content/model/jcr:title] = "Simple Fragment" and s.[/jcr:content/contentFragment] = true
You can also use Query option from crx/de to run query and get the result, but I would consider this more a like an for administrator or developer.
Hi @sreenu539
In term of GUI option I would recommend to use Report Builder functionality from ACS Commons:
It is very flexible and simple to use tool. It allows to define report base on query, and generate results a a table that can be seen in AEM or download as csv file and reviewed offline on local computer.
Below is a sample configuration of report that will return list of links to CF build using Simple Fragment model.
I used following SQL2 query in my report:
SELECT * FROM [dam:Asset] AS s WHERE ISDESCENDANTNODE([/content/dam]) and s.[/jcr:content/model/jcr:title] = "Simple Fragment" and s.[/jcr:content/contentFragment] = true
You can also use Query option from crx/de to run query and get the result, but I would consider this more a like an for administrator or developer.
Views
Likes
Replies