Another dropdown question

[Former Community Member]

I am trying to find a script to do the following:

A=no B=no then C=visible

A=yes B=no then C=visible

A=no B=yes then C=visible

A=yes B=yes then C=hidden

[Niall_O_Donovan]

Hi,

Try similar script in the exit events of the dropdowns:

var vCheck = Number(this.rawValue) + Number(dropB.rawValue); 

switch (vCheck)
{
     case 0:
     letterC.presence = "visible"; 
     break; 
     case 1:
     letterC.presence = "visible"; 
     break; 
     case 2:
     letterC.presence = "hidden"; 
     break; 
}

This should get you started, example here: https://acrobat.com/#d=mvZKlOdoREpa*giIoAaKpA

Good luck,

Niall

ps l just see that Stephen has a similar solution...

[Former Community Member]

This is what I am trying to use:

form1.#subform[0].#subform[4].pp::exit - (JavaScript, client)

var

vCheck = Number(this.rawValue) + Number(p.rawValue);

switch

(vCheck)

{

case 0:

no1.presence

= "visible";

break;

case 1:

no1.presence

= "visible";

break;

case 2:

no1.presence

= "hidden";

break;

}

I am getting "no1" as visible when I have "yes" selected in the first dd

I must be doing something wrong.

[Niall_O_Donovan · Accepted solution]

Did you put similar script in the exit event of the second dropdown?

Were you able to follow the example?

If you need the object presence to be explicitly set up both dropdowns then replace the switch with an if statement like Stephen's example.

I would not be inclined to use single letters for object names. You increase the chance of using a reserved name, like h, w, x, y...

Niall