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TB17
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  • Have you tried using a regular text field labeled "Signature", making the field protected, then saving as a Static PDF (provided it doesn't need to be Dynamic). Then you can use the Pencil tool (under Comments) to "scribble a signature". You probably know this already, but if the form will be comple...

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  • I figured it out using a loop statement...Will leave this posted just in case it helps someone else in the future! var rows = xfa.resolveNodes("TableA.Row[*].Cell2");     for (var i = 0; i < rows.length; i++)    {                var lockField = rows.item(i);        lockField.access = "protected";   ...

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  • Lastly, you might already know this, but also make sure you are referencing the correct paths in your scripts. For example, if your images are placed in another/separate subform called Photos, then the above path is incorrect.Instead, it would be something like:if (this.rawValue == "1"){Photos.Image...

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  • Re: the difference between the Image and Image Field objects... The "Image" object is typically used during design (i.e. the image is added to the form by the form designer - just like what you are doing by pre-placing the image son the form ). If you want the image to be available for future edits ...

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  • If you made sure the export values are set under the Binding tab then it should work. Are you saving the form as a "Dynamic" PDF vs static? If not, try saving as a dynamic form.

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  • See this thread: Require signature field to be signed before submit

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  • P.S. In the solution above, the images reside in the form - you are basically controlling the "presence"...either  "hidden" or "visible". This is with the presumption that only one image is visible at a time. You will have to determine where the images are placed on the form (i.e. stacked on top of ...

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  • NOTE: Below are two simple options. Assign an exported value to the selectable items in the drop-down (i.e. 1,2,3). You would do this on the Binding tab (Specify Item Values)OPTION 1:Use the following script on the "Exit" event of the drop-downif (this.rawValue == "1"){//a "space" character to repre...

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  • I have a single Table ("TableA") with 4 rows - all named "Row". Thus...Row[0], Row[1], Row[2], and Row[3]. Each row has 3 cells. What I'm trying to do is lock the 2nd cell ("Cell2") on every row - essentially locking an entire column.I tried using the following script on a button, but it doesn't wor...

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