Interesting! That's probably what was confusing the issue.

Niall,It is always good to hear from you experts! I'll give it a try on the exit event. But it works now! How strange!

I did find some code in a forum that got me going, although I don't exactly know why.http://forums.adobe.com/message/2445121#2445121Subform VisibilityI implemented Jono Moore's suggestion this way. form1.injurySubformPage1.workLocationDdl::change - (JavaScript, client)sedgwickSubform.presence = "hid...

In a similar situation on the same form, i have this, which doesn't work. I added from the Hierarchy just to see if that made a difference, and it didn't. What could be missing? form1.injurySubformPage1.workLocationDdl::change - (JavaScript, client)injurySubformPage1.sedgwickSubform.presence = "hidd...

Yes, I overlooked those parentheses in the case. Thank you for correcting the script.

Yes, that's very helpful and it explains why a string works and an integer doesn't. I didn't realize they behaved differently. Thank you, Paul!

I just found that if I change the values to a string, the code below works.switch (xfa.event.newText){  // for the change event {    case ("associate"):case ("customer"):And both subforms can appear. Why don't the integers work?

Niall,Yes, that definitely helps. Here' s what I have now, but it doesn't work.var oSubform = form1.injurySubformPage1.typeOfIncidentDdl.rawValue;switch (xfa.event.newText){  // for the change event {    case ("1"):       [one subform becomes visible]     break;     case ("2"):       [another subfor...

I also tried this, but it doesn't work.var oSubform = xfa.resolveNode("form1.#subform[0].typeOfIncidentDdl").rawValue;switch (xfa.event.newText) {    case (oSubform = 1):          assocInfoSubform.presence = "visible";break;     case (oSubform = 2):           custInfoSubform.presence = "visible";bre...

OK. This works, sort of.var oSubform = xfa.resolveNode("form1.#subform[0].typeOfIncidentDdl").rawValue;if (oSubform = 1) {          assocInfoSubform.presence = "visible";The subform becomes visible, but when I change the selection in the dropdown, where the value becomes "2," that field doesn't beco...