I have a form which has fields in it that are hidden/invisible when the form initializes. The form also has a button that can make the field appear under certain conditions using the following:
form1.Subform1.Subform2.TextField1.presence="visible";
But the problem occurs when I try to create a new instance of _Subform2.TextField1. Every time a new instance of TextField1 is generated, it will appear invisible/hidden as well.
How do you go about retreiving the name or reference of the newly generated textfield in order to set it to "visible"?
I am trying to catch it with a for loop, but it is currently not working:
var Subform2Length = Subform2.nodes.length;
_Subform2.addInstance();
for (var nCount = 0; nCount < Subform2Length; nCount ++)
{
if ((Subform2.nodes.item(nCount).className == "subform") & (Subform2.nodes.item(nCount).presence == "invisible"))
{
Subform2.nodes.item(nCount).presence="visible";
}
Any assistance is appreciated. Thanks.
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Try like this in the event where you add the instance for Subform2..
Place it after you add a new Instance..
//Get the InstranceManager count and reduce it by 1. Because Index starts with 0.
var intNewIndex = form1.Subform1.Subform2.instanceManager.count-1;
form1.Subform1.ResolveNode("Subform2[" + intNewIndex + "]").TextField1.presence="visible";
Thanks
Srini
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It worked like a charm. Thank you ver much!
For anyone that uses this: It didn't work initially but it was because the 'ResolveNode' argument was incorrectly capitalised. It should read "resolveNode" instead.
Srini,
I have a question about the code (I am not a programmer by trade and am trying to learn to make Livecycle easier to use):
What is the significance of placing the plus signs (+) around the 'intNewIndex' argument?
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("Subform2[" + intNewIndex + "]")
I am using JavaScript as Language for this script. + sign in Java Script is used for String concatenation. I am concatenating Subform2 with current index in the parenthesis.
So for example, if the intNewIndex value is 1, then after the concatenation the code will look like..
("Subform2[1]")
Hope this helps..
Thanks
Srini
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