Conditional Page Break after Subform

[punit-khatri]

I have two subforms. i  have show and hide subform accoriding to some condition.

Layout should be based on condition as below. lets assume x is a condition

1.  x is true then show the subform1 and subform2 should show start from second page.

2. x is false then hide the subform1 and subform2 should show on first page.

so requirement is  if x is true then i need compulsory page break after subform1.

Please suggest.

Thanks in advance

[radzmar · Accepted solution]

Ok, given you subforms are childs of a body page or subform named "Page", you can add this JavaScript into the contidional break dialog of subform2.

// If this subform is not the first visible under "Page", create a page break.
Page.resolveNodes('#subform.[$.presence eq "visible"]').item(0).name !== this.name

Hope this helps!

[punit-khatri]

I am unable to get this I have below scenario 

under condition ----   Page.resolveNodes('#subform.[$.presence eq "visible"]').item(0).name !== this.name

Am I doing something wrong please help me.

Thanks in advance

[punit-khatri]

I have tried with below also but unable to get page break before second subform "content2"

[radzmar]

Change the scriping language to JavaScript.

[Ankur123456]

Hi ,

[Ankur123456]

Hi Punit, can you please share more details . i am having the same requirement but it's not woking after adding script as mentioned. For ex. i am having x and y internal table .if y internal table is having data then i need to print y internal table on new page . if x internal table is not having any data then y internal table data will be print on first page. can you please share the solution with screen shot. Thanks in advance.