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How to format data in Data prep without the time component

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Level 9

Hello guys,

I need to store a date without the time component and I am thinking to use the Data prep to do this. Any suggestion on how to remove time component from the date?

Thanks

1 Accepted Solution

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Correct answer by
Community Advisor

Hello @Luca_Lattarini 

 

How to format the data will depend on the original format of the data.

 

for eg If your original date format looks like this "2022-09-13 10:00:00".

 

Then you can do something like this:

split(myData," ")[0]

The output will be 2022-09-13

 

Refer to this page for all functions:

Data Prep Mapping Functions | Adobe Experience Platform

 

You can also use the date_part function

 

eg: date_part(date("2022-09-13 12:55:12"), "MM")

 

The output will be 09

 

 


     Manoj
     Find me on LinkedIn

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2 Replies

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Correct answer by
Community Advisor

Hello @Luca_Lattarini 

 

How to format the data will depend on the original format of the data.

 

for eg If your original date format looks like this "2022-09-13 10:00:00".

 

Then you can do something like this:

split(myData," ")[0]

The output will be 2022-09-13

 

Refer to this page for all functions:

Data Prep Mapping Functions | Adobe Experience Platform

 

You can also use the date_part function

 

eg: date_part(date("2022-09-13 12:55:12"), "MM")

 

The output will be 09

 

 


     Manoj
     Find me on LinkedIn

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Level 9

Hello @_Manoj_Kumar_ ,

I used format(date("date as string"),''DD-MM-YYYY') because the date was passed as string

Thnaks