how get the user profile path(/home/users/username/profile) from the session? | Community
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sharathn8223803
Level 2
May 24, 2018
Solved

how get the user profile path(/home/users/username/profile) from the session?

  • May 24, 2018
  • 5 replies
  • 5212 views

I have got the session from the repository login (using username and password), now how to access the profile of the user from the session(/home/users/username/profile). In the end, I need user properties. The request could not be adopted to user properties since its still pointing to the anonymous user.

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    Best answer by Peter_Puzanovs

    Dear Sharat,

    Thank you for your quick response,

    You should be able to adapt org.apache.jackrabbit.api.JackrabbitSession to Authorisable[1] and retrieve property you want.

    E.g. instead of adapting to request, adapt to the session which holds user information you want to present.

    [1] Authorizable (Apache Jackrabbit 2.6.10 API)

    Regards,

    Peter

    5 replies

    Peter_Puzanovs
    Community Advisor
    Peter_PuzanovsCommunity Advisor
    Community Advisor
    May 24, 2018

    Dear Sharat,

    Just to clarify,

    When request comes in the user is not authenticated and is anonymous user. E.g. did not do any authorisation.

    You want to serve user properties of another user(possibly system user) who is authenticated into repository to anonymous user?

    Regards,

    Peter

    S
    sharathn8223803Author
    Level 2
    May 24, 2018

    When the request comes in, the user is trying to signup. I want to access the same user properties( Node )  from the session which i got from the repository login (which call the External login module and creates the same user in aem) .

    Peter_Puzanovs
    Community Advisor
    Peter_PuzanovsCommunity AdvisorAccepted solution
    Community Advisor
    May 24, 2018

    Dear Sharat,

    Thank you for your quick response,

    You should be able to adapt org.apache.jackrabbit.api.JackrabbitSession to Authorisable[1] and retrieve property you want.

    E.g. instead of adapting to request, adapt to the session which holds user information you want to present.

    [1] Authorizable (Apache Jackrabbit 2.6.10 API)

    Regards,

    Peter

    Amit-Tiwari
    Amit-Tiwari
    Level 4
    May 24, 2018

    I dont know why you need the path but you can get the value,

    I am getting logged in user property like this..(i am using AEM 6.2 )

    Session session = slingRequest.getResourceResolver().adaptTo(Session.class);

    UserManager userManager = AccessControlUtil.getUserManager(session);

    if (session != null) {

    final User currentUser = (User) userManager.getAuthorizable(session.getUserID());

    userEmail = currentUser.getProperty(USER_EMAIL) != null ? currentUser.getProperty(USER_EMAIL)[0].getString() : null;

    userName = currentUser.getProperty(USER_NAME) != null ? currentUser.getProperty(USER_NAME)[0].getString() : null;

    here

    USER_NAME = "./profile/familyName";

    USER_EMAIL = "./profile/email";

    rest properties you can look in crx /home/users/geometrixx/aparker@geometrixx.info/profile

    same way you can get others also

      S
      sharathn8223803Author
      Level 2
      May 24, 2018

      Thanks !!

      This is what i came up with

      JackrabbitSession jaSession = (JackrabbitSession) session;

      UserManager auth = jaSession.getUserManager();

      Authorizable authorizable = auth.getAuthorizable(session.getUserID());

      Then u can easily access the user path from there.

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