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wilsonl28824783
Level 2
August 8, 2022
Solved

hide parent subforms based on checked value

  • August 8, 2022
  • 3 replies
  • 1322 views

Hello,

I have a basic flowed structure that has a number if checkboxes each contained within a parent subform. My goal is to have a button at the end to check for all unchecked values and hide their parent subform. Sadly, I am unable to get it to work and I would really like some help with this. 

 

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Best answer by MorisMonk

I think I see what you were trying to do, try something like this

checkAllNodes(Page1);
 
function checkAllNodes(pNode){

	var oNodes = pNode.nodes; 
	var nodesLength = oNodes.length; 

	for (var i = 0; i < nodesLength; i++) { 
    	//xfa.host.messageBox(oNodes.item(i).className)
    	if (oNodes.item(i).className === "subform") {
    		checkAllNodes(oNodes.item(i));
    	}
    	if (oNodes.item(i).name === "chkCheckbox") {
			if (oNodes.item(i).rawValue === 0) {
				oNodes.item(i).parent.presence = "hidden";
			}    		
    	}    	    	
    }
	
}

Probably best to put those Subforms (OptionA, OptionB, etc) under their own Subform and start recursion from it rather than Page1.

3 replies

Pulkit_Jain_
Adobe Employee
Pulkit_Jain_Adobe Employee
Adobe Employee
August 9, 2022

@wilsonl28824783 

You can directly check for the raw value of the field and apply the presence based on the same.

 

var checkboxes = xfa.resolveNodes("chkCheckBox");
    if(checkbox.rawValue == "0")
    {
        [parent subform].presence = "hidden"; 
    }
    break;
    M
    MorisMonk
    Level 4
    August 9, 2022

    If the subforms are static then you could do the following:

    if (Page1.OptionA.chkCheckbox.rawValue === 0) {
	Page1.OptionA.chkCheckbox.parent.presence = "hidden";
}
if (Page1.OptionB.chkCheckbox.rawValue === 0) {
	Page1.OptionB.chkCheckbox.parent.presence = "hidden";
}
      M
      MorisMonkAccepted solution
      Level 4
      August 9, 2022

      I think I see what you were trying to do, try something like this

      checkAllNodes(Page1);
 
function checkAllNodes(pNode){

	var oNodes = pNode.nodes; 
	var nodesLength = oNodes.length; 

	for (var i = 0; i < nodesLength; i++) { 
    	//xfa.host.messageBox(oNodes.item(i).className)
    	if (oNodes.item(i).className === "subform") {
    		checkAllNodes(oNodes.item(i));
    	}
    	if (oNodes.item(i).name === "chkCheckbox") {
			if (oNodes.item(i).rawValue === 0) {
				oNodes.item(i).parent.presence = "hidden";
			}    		
    	}    	    	
    }
	
}

      Probably best to put those Subforms (OptionA, OptionB, etc) under their own Subform and start recursion from it rather than Page1.

        Vijay_Katoch
        Community Advisor
        Vijay_KatochCommunity Advisor
        Community Advisor
        August 9, 2022

        This script will work with any name for the checkbox

         

        checkAllNodes(Page1);

        function checkAllNodes(pNode){

        var oNodes = pNode.nodes;
        var nodesLength = oNodes.length;

        for (var i = 0; i < nodesLength; i++) {
        if (oNodes.item(i).className === "subform") {
        checkAllNodes(oNodes.item(i));
        }
        if (oNodes.item(i).className === "field") {
        if (oNodes.item(i).ui.oneOfChild.className == "checkButton") {
        if (oNodes.item(i).rawValue === 0) {
        oNodes.item(i).parent.presence = "hidden";
        }
        }
        }
        }

        }

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