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christopherp496
Level 2
May 16, 2019
Solved

How to get an id of a newly inserted recipient in JavaScript

  • May 16, 2019
  • 3 replies
  • 2410 views

Hello,

How do you get a recipient id immediately after it was inserted using xtk.session.write?

Example

xtk.session.Write(<recipient _operation="insert" lastName="Martinez" firstName="Peter" xtkschema="nms:recipient"/>);

//How to get the id of this newly added record?

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    Best answer by kapilKochar

    Hi ,

    If you want to use newly created row ID just after creating a record  then I will suggest you to use second way to create records i.e usinf create method.

    var object = namespace.schemaName.create( <schemaName    col1 = {"value1"}    col2 = {"value2"}   /> );

    object.save();

    logInfo(" Id of latest added record is "+ object["id"]);

    Thanks,

    Kapil

    3 replies

    kapilKochar
    kapilKocharAccepted solution
    Level 6
    May 16, 2019

    Hi ,

    If you want to use newly created row ID just after creating a record  then I will suggest you to use second way to create records i.e usinf create method.

    var object = namespace.schemaName.create( <schemaName    col1 = {"value1"}    col2 = {"value2"}   /> );

    object.save();

    logInfo(" Id of latest added record is "+ object["id"]);

    Thanks,

    Kapil

      pierrec70731455
      pierrec70731455
      Level 4
      May 16, 2019

      Hi,

      to complete kapscool's response, I don't think you get the rowid but THE (recipient) id with his method

      var recipient= nms.recipient.create( <schemaName    lastName= {"Martinez"}    firstName= {"Peter"}  /> );
      recipient.save();
      logInfo(" Id of latest recipient added is "+ recipient["id"]);

      You can also use the NLWS create method (doc) :

      var recipient= NLWS.nmsRecipient.create(
                {recipient: {
                  lastName: "Martinez",
                  firstName: "Peter"
                  }});
      recipient.save();
      logInfo(" Id of latest recipient added is " + recipient.id);

      Kind regards,

      Pierre

        C
        christopherp496Author
        Level 2
        May 16, 2019

        Thank You!

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