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SOLVED

Delete a node in XML

Avatar

Level 2

Hi

I have a XML that is getting generated on click of a button in the form.

I am using  xfa.data.saveXML("pretty"); to generate the XML.

Following is the XML,

<?xml version="1.0" encoding="UTF-8"?>

<xfa:data xmlns:xfa="http://www.xfa.org/schema/xfa-data/1.0/">

   <ELEMENT>

      <DATA>

         <ROW_IID>0</ROW_IID>

         <PARENT>0</PARENT>

         <CHILD>0</CHILD>

      </DATA>

      <NAME> 

          <FNAME>0</FNAME>

          <LNAME>0</LNAME>

      </NAME>

   </ELEMENT>

</xfa:data>

I want to delete the <NAME> node in the XML and assign the manipulated XML to some text field.

Could anyone please let me know how to do the same?

Thanks:)

1 Accepted Solution

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Correct answer by
Level 10

Hi,

Considering you want the output as a string you could use XSLT, so something like (which copies all xml nodes except the NAME one);

var stylesheet =

    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:output method = "xml" omit-xml-declaration = "yes" indent = "yes"/>   

        <xsl:template match="@*|node()">

            <xsl:copy>

                <xsl:apply-templates select="@*|node()"/>

            </xsl:copy>

        </xsl:template>

        <xsl:template match="NAME"/>

    </xsl:stylesheet>

var txt = $data.ELEMENT.applyXSL(stylesheet.toXMLString());    

console.println(txt)

You could also use;

$data.ELEMENT.nodes.remove($data.ELEMENT.NAME)

console.println($data.ELEMENT.saveXML("pretty"));

Regards

Bruce

View solution in original post

2 Replies

Avatar

Correct answer by
Level 10

Hi,

Considering you want the output as a string you could use XSLT, so something like (which copies all xml nodes except the NAME one);

var stylesheet =

    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:output method = "xml" omit-xml-declaration = "yes" indent = "yes"/>   

        <xsl:template match="@*|node()">

            <xsl:copy>

                <xsl:apply-templates select="@*|node()"/>

            </xsl:copy>

        </xsl:template>

        <xsl:template match="NAME"/>

    </xsl:stylesheet>

var txt = $data.ELEMENT.applyXSL(stylesheet.toXMLString());    

console.println(txt)

You could also use;

$data.ELEMENT.nodes.remove($data.ELEMENT.NAME)

console.println($data.ELEMENT.saveXML("pretty"));

Regards

Bruce

Avatar

Level 2

Hi Bruce,

Its working!!..Thanks you so much:-)