Hello guys, I'm trying to create a checkbox on a dialog through its clientLib's javascript file.
i tried using
but I couldn't make it work.
Can anyone help me please?
Solved! Go to Solution.
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Hey @caiosheperd ,
Could you please help with the requirement? I wanted to understand why you want to create the checkbox using code when you already have OOTB?
and still, if you want to do it so there are a couple of steps -
1. You will have to define the granite:class to container or tab where you can identify the exact location with a custom class.
2. Once it is created, you can write the code to append the line of code using javascript. For Example, the below code I am using to create a button in multifield-
(function(document, $) {
"use strict";
$(document).on("foundation-contentloaded", function(e) {
const MULTIFIELD_ACTION = '.cmp-editor-multifield_actions';
const MULTI_ITEM = 'coral-multifield-item-content';
const FORM_FIELD = '.coral-Form-field[name="./banners/item0/./products/item{itemone}/./imageNumber"]';
let items = $(MULTIFIELD_ACTION).find(MULTI_ITEM);
for (let i = items.length - 1; i < items.length; i++) {
let itemone = i;
$(FORM_FIELD.replace('{itemone}', itemone)).after("<button type='button' is='coral-button' variant='default' onclick='myFunction()' class='_coral-Button _coral-Button--primary' size=M'> <coral-button-label class='_coral-Button-label'>Preview Product</coral-button-label></button>");
}
});
})(document, Granite.$);
Let me know your requirement, I can help you with the approach.
Thanks
Hey @caiosheperd ,
Could you please help with the requirement? I wanted to understand why you want to create the checkbox using code when you already have OOTB?
and still, if you want to do it so there are a couple of steps -
1. You will have to define the granite:class to container or tab where you can identify the exact location with a custom class.
2. Once it is created, you can write the code to append the line of code using javascript. For Example, the below code I am using to create a button in multifield-
(function(document, $) {
"use strict";
$(document).on("foundation-contentloaded", function(e) {
const MULTIFIELD_ACTION = '.cmp-editor-multifield_actions';
const MULTI_ITEM = 'coral-multifield-item-content';
const FORM_FIELD = '.coral-Form-field[name="./banners/item0/./products/item{itemone}/./imageNumber"]';
let items = $(MULTIFIELD_ACTION).find(MULTI_ITEM);
for (let i = items.length - 1; i < items.length; i++) {
let itemone = i;
$(FORM_FIELD.replace('{itemone}', itemone)).after("<button type='button' is='coral-button' variant='default' onclick='myFunction()' class='_coral-Button _coral-Button--primary' size=M'> <coral-button-label class='_coral-Button-label'>Preview Product</coral-button-label></button>");
}
});
})(document, Granite.$);
Let me know your requirement, I can help you with the approach.
Thanks
Hi @caiosheperd : Not sure what is your exact requirement.
But, if you want to show a checkbox conditionally, you can create a checkbox field and hide it initially and then show/hide based on your condition.
You can refer links here to see how show/hide works: https://experienceleaguecommunities.adobe.com/t5/adobe-experience-manager/how-to-show-hide-feilds-us...
thanks.
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