


I am trying to compute the label of a new list referencing the vars.filename variable, but the filename includes the sftp file path. I just want to use the file name without the path included. How can I do this?
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You may use the function
FileName($(vars/@filename))
Hi @rebeccateng12,
Was the given solution helpful to resolve your query or do you still need more help here? Do let us know.
Thanks!
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