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A
akshay2
October 18, 2019
Solved

Debugging Adobe Campaign Javascript

  • October 18, 2019
  • 4 replies
  • 6471 views

Being new to Campaign I am having trouble debugging JS code In Campaign..

I have a general question on the debugging aspect of the Code ( javascript )

  1. How to see the XML that is being returned . I tried doing logInfo( response ) in the below code, but nothing is shown

var query = xtk.queryDef.create( 
  <queryDef schema="nms:recipient" operation="get">   
    <select>     
      <node expr="@firstName"/>     
      <node expr="@lastName"/>     
      <node expr="@email"/>   
    </select>       
  </queryDef>)

var response = query.ExecuteQuery()
lofInfo( response.recipient ); =>  shows nothing

2. What are the tips/guidelines  for debugging the javascirpt code  in Campaign ?  how do the experts do it   :-)

cheers

akshay

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    Best answer by Jyoti_Yadav

    Hi,

    Use below syntax:

    var query = xtk.queryDef.create(
      <queryDef schema="nms:recipient" operation="get">  
        <select>    
          <node expr="@firstName"/>    
          <node expr="@lastName"/>    
          <node expr="@email"/>  
        </select>      
      </queryDef>)

    var response = query.ExecuteQuery()

    logInfo("response: "+ response.toXMLString());

    Also if your output has more than one row then use for each loop.

    for each( var res in response){

    logInfo("response: "+ response.toXMLString());

    }

    Thanks.

    4 replies

    Raj_Ganta-1
    Raj_Ganta-1
    October 18, 2019

    hi,

    logInfo( response.@firstName) will give log or for that matter any attribute you used in select node

    2. What are the tips/guidelines for debugging the javascript code in the Campaign ?  how do the experts do it   :-)

    use external debugger tools for the syntax and campaign does not have Linting to identify potential errors

      Jyoti_Yadav
      Jyoti_YadavAccepted solution
      October 21, 2019

      Hi,

      Use below syntax:

      var query = xtk.queryDef.create(
        <queryDef schema="nms:recipient" operation="get">  
          <select>    
            <node expr="@firstName"/>    
            <node expr="@lastName"/>    
            <node expr="@email"/>  
          </select>      
        </queryDef>)

      var response = query.ExecuteQuery()

      logInfo("response: "+ response.toXMLString());

      Also if your output has more than one row then use for each loop.

      for each( var res in response){

      logInfo("response: "+ response.toXMLString());

      }

      Thanks.

        Marcel_Szimonisz
        Community Advisor
        Marcel_SzimoniszCommunity Advisor
        Community Advisor
        October 21, 2019

        Hello,

        You need to display res.toXMLString()  instead of response or directly res.@firstName res.@lastName or res.@email

        Marcel

          A
          akshay2Author
          October 28, 2019

          thanks a lot @jyotij .. I owe you a beer

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