Display single item from a list In sightly

Question

Hello Team,The below code works fine which displays two records .

but this code is not working to display one record

. Can you please help me with how i can display one record successfully.?

EstebanBustamante · Accepted Answer

Hi,

If you know the index of the record you want to show, you don't have to iterate through the array; you can access it directly using its index, like this:

My first element: ${myModel.dummyObj[0] @ context='html'}

If you need to display a specific element of the array but you don't know its index, you can iterate through the array and compare each element to determine if it matches the one you need to render. For example: https://experienceleaguecommunities.adobe.com/t5/adobe-experience-manager/get-value-of-index-2-in-a-slightly-list/m-p/218606 another example

<ul data-sly-list="${currentPage.listChildren}">
    <li data-sly-test=${itemList. first}>This is the first element: ${item.title}</li>
</ul>

You can find more examples in the HTL spec: https://github.com/adobe/htl-spec/blob/master/SPECIFICATION.md

Hope this helps.

This is the first element: ${item.title}

You can find more examples in the HTL spec: https://github.com/adobe/htl-spec/blob/master/SPECIFICATION.md Hope this helps.

KNan · Answer

Hi @grishmaba Please try like this,

${childList.first}

The following default variables are available within the scope of the list:item: The current item in the iteration.itemList: Object holding the following properties:index: zero-based counter (0..length-1).count: one-based counter (1..length).first: true if the current item is the first item.middle: true if the current item is neither the first nor the last item.last: true if the current item is the last item.odd: true if index is odd.even: true if index is even.

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