Double Custom Trafic Variable (prop) based Segments effect on Visits | Community
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marion33678522
marion33678522
Level 5
May 31, 2017
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Double Custom Trafic Variable (prop) based Segments effect on Visits

  • May 31, 2017
  • 2 replies
  • 1155 views

Hello Adobe Community !

I'm trying hard to figure out an odd behaviour but I cannot yet grasp the explanation.

I'm currently testing 2 segments ( that are almost exactly the same ) , one has a "Hit" container (let's call it segment "A"), the other one has a "Visit" container (let's call it segment "B") on the same custom traffic variable ( lets call it propX).

I was predicting that I would have the same number of visits if i segmented the visits metric with segment A or B.
This showed already alright on both of the segments previews.
But on the workspace, I found out that there were more visits using the B segment.

I found out what was causing this - I remembered that I had already another segment (let's call it "C", also on a custom trafic variable)with a Hit container on the panel header, based on another prop ( let's call it prop Y).

If I take out this segment the number of visits is the same regardless of the segment (A or B).

So, how is it possible, that 

(C+B)visits > (C+A)visits

but

(B)visits = (A)visits ?


This almost looks like a math topology problem ! Sorry for the odd formalism on the 2 previous wannabe equations...

Cheers !

Mario

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    Best answer by Urs_Boller

    hi mario

    yes, this is possible. i try to explain.

    segment A only contains hits where propX is set, no other hits. in segment B there are all hits where at least one hit has propX. you should see a difference in occurances or page views if you only look at those two segments.

    now adding sehment C:

    A+C: only Hits (and corresponding Visits) where both PropX ANd propY are set on the same Hit

    B+C: shows Hits (and corresponding Visits) where propY is set on every hit BUT only needs one hit of the Visit to have propX. Because B is a visit segment, the propX must not be on the same hit ad the hit with propY. this means, that the number of visits with B+C should be higher than A+B.

    does this makes sense? is it possible that a visit can have propY but never propX on the same hit (but elsewhere in the visit)?

    maybe this is easier to explain with pictures ...

    regards

    urs

    2 replies

    Urs_Boller
    Community Advisor
    Urs_BollerCommunity AdvisorAccepted solution
    Community Advisor
    June 1, 2017

    hi mario

    yes, this is possible. i try to explain.

    segment A only contains hits where propX is set, no other hits. in segment B there are all hits where at least one hit has propX. you should see a difference in occurances or page views if you only look at those two segments.

    now adding sehment C:

    A+C: only Hits (and corresponding Visits) where both PropX ANd propY are set on the same Hit

    B+C: shows Hits (and corresponding Visits) where propY is set on every hit BUT only needs one hit of the Visit to have propX. Because B is a visit segment, the propX must not be on the same hit ad the hit with propY. this means, that the number of visits with B+C should be higher than A+B.

    does this makes sense? is it possible that a visit can have propY but never propX on the same hit (but elsewhere in the visit)?

    maybe this is easier to explain with pictures ...

    regards

    urs

      marion33678522
      marion33678522Author
      Level 5
      June 1, 2017

      Hello!

      thanks a lot urs.boller​ !

      Yes i see a little bit better, I made a drawing with your explanation !

      And also, when I remembered that propY had more hits than prop X, It became clearer to me.

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