Hi EmilyOne possible solution is to classify the list variable (or prop
list if you don't need to see conversion) with name and description.
Template: list1 = name_image1|description_image1,
name_image2|description_image2, name_image3|description_image3Example:
list1 = image33|tree_oak, image43|tree_elm, image77|tree_abcAt the AA
you can create 2 classifications for list1: Image Name and Image
Description. You'll have something like this: Hope this help you
Regards,Brandão.