Avatar

Correct answer by
Level 6

Yes!  This is even better, but I didn't know until now that there is a presence property on the fill.  Try this:

if (this.rawValue == 0)

{  

    hc1.rawValue=0;

    hc2.rawValue=0;

    hc3.rawValue=0;

    hcgray.resolveNode("value.rectangle.#fill").presence = "hidden";

    sfrhc1.rawValue=1;

    sfrhc2.rawValue=1;

    sfrhc3.rawValue=1; 

    sfrhcgray.resolveNode("value.rectangle.#fill").presence = "visible";   

}  

else

{  

    hc1.rawValue=1;

    hc2.rawValue=1;

    hc3.rawValue=1;

    hcgray.resolveNode("value.rectangle.#fill").presence = "visible";

    sfrhc1.rawValue=0;

    sfrhc2.rawValue=0;

    sfrhc3.rawValue=0;

    sfrhcgray.resolveNode("value.rectangle.#fill").presence = "hidden";

}

View solution in original post