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Yes! This is even better, but I didn't know until now that there is a presence property on the fill. Try this:
if (this.rawValue == 0)
{
hc1.rawValue=0;
hc2.rawValue=0;
hc3.rawValue=0;
hcgray.resolveNode("value.rectangle.#fill").presence = "hidden";
sfrhc1.rawValue=1;
sfrhc2.rawValue=1;
sfrhc3.rawValue=1;
sfrhcgray.resolveNode("value.rectangle.#fill").presence = "visible";
}
else
{
hc1.rawValue=1;
hc2.rawValue=1;
hc3.rawValue=1;
hcgray.resolveNode("value.rectangle.#fill").presence = "visible";
sfrhc1.rawValue=0;
sfrhc2.rawValue=0;
sfrhc3.rawValue=0;
sfrhcgray.resolveNode("value.rectangle.#fill").presence = "hidden";
}
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