Something that should be simple has turned into a bit of a trial. I have an Adobe form with three tables with different columns. Based on a variable passed to the form say, "number_of_tests" one of the tables should be visible.
This works fine when the subforms are set to "invisible" by default and then made "visible". However, it does not work when the default value is "hidden". Why does this matter? Well, the "invisible" element still affects the layout of the form so I need it "hidden" (exclude from layout). Any clue would be greatly appreciated.
Thanks Radzmar...good eye for detail. I was jostling about the subforms in an attempt to structure them differently and pasted in the wrong code in the discussion.
I have tried the form.ready, layout.ready and initialize....they all had the same effect. I'm able to make visible invisible elements but am not able to make visible hidden elements. Seems the code should be the same for both of them. I made sure to try your code, and it had the same effect. Do hidden elements require something in addition to invisible elements?
I will take a look at your link to the developer specs, I appreciate that link. As you can tell, I'm pretty new with adobe forms.