Change Events (Show/Hide Subforms)

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Mancini21

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Mancini21

Mancini21

16-09-2009

Hi guys i need some help, i have a some subForms that i want to manipulate with a dropdown list, and i've tried to do this with this code in the exit event,

if (this.rawValue ==1) {

xfa.resolveNode("form1.theForm.subForm1").presence= "invisible";

xfa.resolveNode("form1.theForm.subForm2").presence= "visible";
}

else if(this.rawValue ==2) {

xfa.resolveNode("form1.theForm.subForm3").presence= "visible";

xfa.resolveNode("form1.theForm.subForm4").presence= "invisible";

}

This is not working. The subforms are not working. I think that here if(this.rawValue ==1), the number, is the position of the list that i inserted in the drop down list object. Am i correct?

If someone can help i would apreciate.

I am also attaching the file.(I want to do in the dropdown list the same behavior of the checkboxes.)

Thanks.

Regards

Mancini.

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xrum

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xrum

xrum

16-09-2009

to see what number refers to which drop down option.

select your drop down, in the properties Binding tab.

check "specify Item values" and you'll see it

good luck